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7x^2+10=x+22
We move all terms to the left:
7x^2+10-(x+22)=0
We get rid of parentheses
7x^2-x-22+10=0
We add all the numbers together, and all the variables
7x^2-1x-12=0
a = 7; b = -1; c = -12;
Δ = b2-4ac
Δ = -12-4·7·(-12)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{337}}{2*7}=\frac{1-\sqrt{337}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{337}}{2*7}=\frac{1+\sqrt{337}}{14} $
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